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2x^2-98x=-720
We move all terms to the left:
2x^2-98x-(-720)=0
We add all the numbers together, and all the variables
2x^2-98x+720=0
a = 2; b = -98; c = +720;
Δ = b2-4ac
Δ = -982-4·2·720
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3844}=62$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-62}{2*2}=\frac{36}{4} =9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+62}{2*2}=\frac{160}{4} =40 $
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